datagrid怎么绘制静态数据不报404错误 - jQuery MiniUI

<div class="mini-panel" style="width: 100%;height: 100%;" borderStyle="border:0" bodyStyle="padding:0;" showHeader="false">
<div id="datagrid1" class="mini-datagrid" style="width:100%;height:100%;" allowResize="false"
multiSelect="true" >
<div property="columns">
<div type="checkcolumn"></div>
<div type="indexcolumn"></div>
<div field="loginname" width="120" headerAlign="center">员工帐号</div>
<div field="name" width="120" headerAlign="center">姓名</div>
</div>
</div>
</div>
<script>
mini.parse();
var grid = mini.get("datagrid1");
var data = [{"id":"1122121","loginname":"12","name":"张三"}];
grid.setData(data);
grid.load();
</script>

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